Z mod 3/Gruppenring/Rechenbeispiel/1/Aufgabe/Lösung

Es ist

${}{\begin{aligned}{\left(3T^{0}-2T^{1}+5T^{2}\right)}\cdot {\left(4T^{0}-6T^{1}+5T^{2}\right)}&={\left(3T^{0}+5T^{1}+5T^{2}\right)}\cdot {\left(4T^{0}+T^{1}+5T^{2}\right)}\\&=5T^{0}+3T^{1}+T^{2}+6T^{1}+5T^{2}+4T^{0}+6T^{2}+5T^{0}+4T^{1}\\&=6T+5T^{2}.\end{aligned}}$

Zur gelösten Aufgabe